9w^2+18w=1080

Solution for 9w^2+18w=1080 equation:

9w^2+18w=1080

We move all terms to the left:

9w^2+18w-(1080)=0

a = 9; b = 18; c = -1080;
Δ = b2-4ac
Δ = 182-4·9·(-1080)
Δ = 39204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{39204}=198$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-198}{2*9}=\frac{-216}{18}
=-12
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+198}{2*9}=\frac{180}{18}
=10
$